Today I was reading the Michèle Audin’s book, there is a statement she might had skipped:
If Lie group has a Symplectic action on Symplectic Manifold
, that is
, then, for any
, the flow
of the fundamental vector fields
generated by
preserves the Symplectic form.
Here the fundamental vector field is defined as , where
is the orbit map:
, with
, and
is the identity in Lie group
.
This statement is not so obviously for me, so I took a couple of hours to think about it, here is my proof.
Actually, the action of the flow on
is same as the action of
(and that leads to the desired consequence immediately), where the
is the expoential from Lie algebras to Lie Groups, indeed, for any
, the result of
forms a parameterized curve on
(if I may, I will denote it by
), if we can prove it satisfies the initial condition
, and the differential equation
, then the two actions will be same.
The initial condition is obviously satisfied, notice that the curve can be written as , and if we denoted by
, the action of the left multiplication, hence by the chain rule we have:
That is obviously the value , there is another interesting view if we denoted by
, the flow induced by the fundamental vector field
(actually, this Is a widely used notion for the flow of a vector field, for example, da Silva’s Lectures on Symplectic Geometry), then the result we proved is a really beautiful and harmonic formula:
The on the left hand side is the flow on Manifolds, the
on the right hand side is the flow on Lie Groups, they were attached perfectly via the fundamental vector field.